If you have abs(), you can use the following as a fallback: min(a, b) = (a + b -...

		layer8 on Aug 18, 2022 \| parent \| context \| favorite \| on: Show HN: I made a web-based notepad with a built i... If you have abs(), you can use the following as a fallback: min(a, b) = (a + b - abs(a − b)) / 2 max(a, b) = (a + b + abs(a − b)) / 2